Thursday, October 19, 2017

My Maths Classroom.... Closure

Direct LINK to the form.

[Updated: 21 October 2017]
Click HERE to learn what your classmates shared about their learning experiences in the class :)



Responses to selected responses will be shared in the Google Classroom.
You will be alerted via an email when it is 'delivered'.

Saturday, October 7, 2017

Revision: SST 2016 Maths S1 Paper 2 Q4b

There are 2 ways to find xy :

Method 1: (as shown in the suggested solution document, in GoogleSite)
It uses the special products (or algebraic identities) to solve.
Note that we did not need to find x or y value in this method.




Method 2:

In this method, we attempt to solve 2 simple simultaneous equations to find out the values of x and y.
With this, we find xy.




Some of you actually use "Guess and Check" method, where you try to list down possible pairs of integers that can be add together to give 7, followed by check using the other equation. 
Do NOT use this method as it opens up many possibilities which would not worth the time to check one by one.




Revision: SST 2016 Maths S1 Paper 2 Q6

One strategy to solve this problem is to write down and organise the information available.
From there, try to pull the information together to form an equation to solve for the unknowns.





Revision: SST 2016 Maths S1 Paper 2 Q7

Given the speed of the following:
  • Adam     160 m/min
  • Bernard     120 m/min

Strategy: Put all information in a diagram and draw 'relationships' (with reference to the speed-time-distance formula) to form equations



Since we do not know the distance for the race, let it be d metres.
Since we are not given the time taken by Adam to complete the race, let the time taken be t minutes.
The 2nd diagram shows the position of Adam, Bernard and Charlie at t minutes.
Hence, what's common for all three boys is the duration, t minutes.

Using the formula, Distance = Speed x Time



With this, we know that distance covered by Charlie (at t min) = 800 m - 250 m = 550

Substitute d = 550 into first equation (i.e. time taken by Adam), we have
Time taken, t = 800 ÷ 150 = 5 minutes

Hence, Charlie's speed
= Distance covered/ Time taken
= 550 m ÷ 5 min 
= 110 m/min     (Ans)

Note: There are other 'shortcuts' to solve the problem. However, the above will give you an idea how to solve the unknown(s) systematically using the known relationships for speed-time-distance.

Revision: SST 2016 Maths S1 Paper 2 Q8

Watch the video clip (no sound) to understand the diagram


(i) Since the length of the paper is 30 cm, from the diagram, we note that
Height of letter in terms of x = 30 - x - x     cm, which is same as 30 - 2x    cm

(ii) Given the ratio Height : Width = 8 : 5
Since we can express the height of the letter in terms of x, we shall try to express the width of the letter in terms of x, too.


Refer to the line (in orange), width = 3 + x     cm

Now, with these information, we use the ratio to form the equation and use it to find x:


(iii) To find the perimeter of the letter, we need to find the (marked out in the diagram)








Monday, October 2, 2017

20171002: Revision - Algebra

Mentioned in class, there's more than one way to do (i).
I've presented 3 ways below how to show LHS of equation = RHS of equation.
We also spoke about NOT using any numbers to do the "shown" question. Remember that "hence" means make use of what is given in (i) to do (ii)


Practice for similar type of Question: CGS 2015 S2 Mid-Year Section A Q7

Saturday, September 30, 2017

6 AM Quiz: It's Algebra!

Click HERE to access the Quiz to submit your answers.
  • Click HERE to view responses

Answer scoreBonus score
Q11-
Q222
Q321
Q422

For quick reference, the questions in the quiz are:







Suggested Solution
(updated: 3 October 2017)